1.

A gas expands from a volume of 1m^(3) to a volume of2m^(3) against an external pressure of10^(5) Nm^(-2). The work done by the gas will be

Answer»

`10^(5) kJ `
` 10^(2) kJ`
` 10^(2) J`
`10^(3)J`

SOLUTION :`w = - PDeltaV =- 10^(5) NM^(-2) ( 2-1) m^(3) =- 10^(5) Nm = - 10^(5) J = -10^(2) kJ `


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