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A gas expands from a volume of 1m^(3) to a volume of2m^(3) against an external pressure of10^(5) Nm^(-2). The work done by the gas will be |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(5) kJ `<br/>` 10^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) kJ`<br/>` 10^(2) <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>`<br/>`10^(3)J`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`w = - PDeltaV =- 10^(5) <a href="https://interviewquestions.tuteehub.com/tag/nm-579234" style="font-weight:bold;" target="_blank" title="Click to know more about NM">NM</a>^(-2) ( 2-1) m^(3) =- 10^(5) Nm = - 10^(5) J = -10^(2) kJ `</body></html> | |