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A gas is found to obey the law `P^(2)` V= constant the innitial temperature and volume are `T_(0)` and `V_(0)`. If the gas expands to volume `2V_(0)` , its final temperature becomes-A. `sqrt(2) T_(0)`B. `2T_(0)`C. `T_(0)//2`D. ` T_(0)//sqrt(2)` |
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Answer» Correct Answer - A `P^(2)V` = constant `implies (T^(2))/(V)` = constant `implies T_(2) = sqrt((v_(2))/(v_(1))) T_(1) = sqrt2 T_(0)` |
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