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A gaseous hydrocarbon has 85% carbon and vapour density of 28. The possible formula of the hydrocarbon will beA. `C_(3)H_(6)`B. `C_(2)H_(4)`C. `C_(2)H_(2)`D. `C_(4)H_(8)` |
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Answer» Correct Answer - D `C: H=(85)/(12):(15)/(1)=,1:2` `:.` Empirical formula ` =CH_(2)` Empirical formula weight `=12+2xx1=14` Mol. Wt. `=2xx V D= 2xx28 =56, n=(56)/(14)=4` Now, `MF-nxx` empirical formula `4xxCH_(2)=C_(4)H_(8)` |
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