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A gaseous hydrocarbon on complete combustion gives 3.38 g of `CO_(2)` and 0.690 g of `H_(2)O` and no other product. The empirical formula of the hydrocarbon isA. `CH`B. `CH_(2)`C. `CH_(3)`D. The data is not complete |
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Answer» Correct Answer - A `44 g CO_(2)` = 2 mol carbon `3.38 g CO_(2)` = 0.0768 mol carbon `18 g H_(2)O` = 2 mol of hydrogen atoms `0.690 g H_(2)O` = 0.0767 mol hydrogen atom Mole ratio of C:H = 1:1 `:.` Empiriccal formula of hydrocarbon is CH |
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