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A gaseous mixture consists of 16 g of helium (He) and 16 g oxygen (O_2), the ratio C_P/C_V of the mixture is = ...... |
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Answer» 1.4 For 16 g `O_2, n_2=16/32=1/2` For mixture of gas, `C_V=(n_1C_(V1)+n_2C_(V2))/(n_1+n_2)` where, `C_V=f/2 R` `C_P=(n_1C_(P1)+n_2C_(P2))/(n_1+n_2)` where, `C_P=(f/2+1)R` For `H_2, f_1=3, n_1=4`, For `O_2, f_2=5, n_2=1/2` `therforeC_P/C_V=(n_1((f_1)/2+1)R+n_2((f_2)/2+1)R)/(n_1f_1R+n_2(f_2R))` `=(4(3/2+1)R+1/2(5/2+1)R)/(4(3/2R)+1/2xx5/2R)` `=(4xx5/2R + 1/2xx7/2R)/(6R+5/4R) =(10R+7/4R)/(6R+5/4R)` `=(40R + 7R)/(24R+5R)=47/29`=1.62 |
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