A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas ‘A’ with gamma = (C_p/C_v) = 5/3and another gas .B. withgamma = 7/5at a certainof gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation PV^(19//13)= constant in an adiabatic process [5^(19//13) = 10.5]If T is raised by 1k from 300 k. Find the percentage change in volume.

A gaseous mixture enclosed in a vessel of volume V consists of one gra

1.	A gaseous mixture enclosed in a vessel of volume V consists of one gram mole if a gas ‘A’ with gamma = (C_p/C_v) = 5/3and another gas .B. withgamma = 7/5at a certainof gases A and B are 4 and 32 respectively. The gases do not react with each other and are assumed to be ideal. The gaseous mixture follows the relation PV^(19//13)= constant in an adiabatic process [5^(19//13) = 10.5]If T is raised by 1k from 300 k. Find the percentage change in volume.
Answer» 0.003 0.006 0.007 0.008 Answer :C