A gaseous sample is generally allowed to do only expansion//compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion//compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V), so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. In the above problem

A gaseous sample is generally allowed to do only expansion//compressio

1.	A gaseous sample is generally allowed to do only expansion//compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion//compression the states of gases are not defined). The work done can be calculated using dw= -P_(ext)dV while in case of reversible process the work done can be calculated using dw= -PdV where P is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since P=(nRT)/(V), so w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i))) Since dw= PdV so magnitude of work done can also be calculated by calculating the area under the PV curve of the reversible process in PV diagram. In the above problem
Answer» work done by the gas in `I^(ST)` SAMPLE `gt` work done by gas in `II^(nd)` sample work done by gas in `II^(nd)` sample `gt` work done by gas in `I^(st)` sample work done by gas in `I^(st)` sample`=` work done by gas in `II^(nd)` sample None of these Solution :Work done in isothermal PROCESS is more than in ADIABATIC process as shown in the DIAGRAM above.