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InterviewSolution
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A gases mixture contains oxygen and nitrogen in the ratio `1 : 4` by weight. Therefore, the ratio of the number of molecules is:A. (a)1:4B. (b)1:8C. (c )7:32D. (d)3:16 |
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Answer» Correct Answer - C Let mass of oxygen `=1 g`, Then mass of nitrogen `=4 g` Mol. Wt. of `N_(2)=28 g`, Mol. Wt. of `O_(2)=32 g` `28 g` of `N_(2)` has`=6.02xx10^(23)` molecules of nitrogen `4 g` of `N_(2)` has`=(6.02xx10^(23))/28xx4` molecules of nitrogen `=(6.02xx10^(23))/7` molecules of nitrogen `32 g` of `O_(2)` has`=6.02xx10^(23)` molecules of oxygen `:. 1 g of O_(2)` has`=(6.02xx10^(23))/32xx1=(6.02xx10^(23))/32` molecules of oxygen Thus, ratio of molecules of oxygen: nitrogen `=(6.02xx10^(23)//32)/(6.02xx10^(23)//7)=7:32`. |
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