A geostationary satellite is revolving around the earth. To make it escape from gravitational field of earth its velocity must be increase ….....

A geostationary satellite is revolving around the earth. To make it es

1.	A geostationary satellite is revolving around the earth. To make it escape from gravitational field of earth its velocity must be increase ….....
Answer» `100%` `41.4%` `50%` `59.6%` Solution :`IMPLIES` Centripetal force on satellite = Gravitional force between satellite and earth. `(mv_0^2)/R = (GM_em)/r^2` (r = distance of satellite from the centre of earth) `v_0^2=(GM_e)/r` `:.v_0 = (GM_e)/r ""...(1)` Escape speed for satellite `:. v_e = sqrt(2GM_e)/r ""...(2)` `:. v_e =sqrt2 sqrt((GM_e)/r)` `:. v_e = sqrt2 v_0` `:. v_e =1.414 v_0` `:. v_e/v_0 = 1.414` `:. (v_e-v_0)/v_0 =(1.414-1)/1 = 0.414` `:. (v_e-v_0)/v_0xx100% =41.4%`