1.

A girl swings in a cardle with period pi//4 second and amplitude 2m. A boy standing infront of it blows a whistle of natural frequency 1000Hz. The minimum frequency as heard by the girl is (Velocity of sound in air is 320ms^(-1))

Answer» <html><body><p>`850Hz`<br/>`1000Hz`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/750hz-335447" style="font-weight:bold;" target="_blank" title="Click to know more about 750HZ">750HZ</a>`<br/>`950Hz`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`V_(0)=V_(g)=omegaA=(2piA)/(T)=(2pixx2)/(pi//4)=16m//s` <br/> `V_(s)=V_(b)=0n_(<a href="https://interviewquestions.tuteehub.com/tag/min-548008" style="font-weight:bold;" target="_blank" title="Click to know more about MIN">MIN</a>)=((<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>-V_(0))/(V))n`</body></html>


Discussion

No Comment Found