1.

A girl swings in a cardle with period pi//4 second and amplitude 2m. A boy standing infront of it blows a whistle of natural frequency 1000Hz. The minimum frequency as heard by the girl is (Velocity of sound in air is 320ms^(-1))

Answer»

`850Hz`
`1000Hz`
`750HZ`
`950Hz`

SOLUTION :`V_(0)=V_(g)=omegaA=(2piA)/(T)=(2pixx2)/(pi//4)=16m//s`
`V_(s)=V_(b)=0n_(MIN)=((V-V_(0))/(V))n`


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