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A given mass of gas at a pressure of 0.75 m of mercury is compressed isothermally until its volume is reduced to 3/4th of its volume. It is then made to expand adiabatically to a volume 1/5 times greater than its original volume. Calculate the final temperature if its initial temperature was 290 K.(Y=1.4) |
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Answer» <P> Solution :`P _(2) = (p_(1) V_(1)//V _(2)) = (0.75 xx 4//3) = 1 m of HG. T _(2)= T (V _(2) //V_(3)) ^( gamma -1) . V _(2) = (3//4) V _(1), V _(3) =[V _(1) + (V _(1) //5)]T_(2) = 290 xx (5//8) ^(0.4) = 240.3 K` |
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