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A glass bulb can withstand a pressure of 2 atm. It constains air at a temperature of 303 K and at one atmospheric pressure. What is the temperature at which the bulb bursts ? (Neglect the expansion of the bulb) gamma = 1.4

Answer»

SOLUTION :`P _(1) = 1 atm, T _(1) = 303 K P _(2) = 2 atm`
`((P _(2))/( P _(1))) ^( GAMMA -1) = ((T _(2))/(T_(1))) ^(gamma)`
`(2) ^( 1.4-1) = ((T_(2))/( 303)) ^(1//4)`
`0.4 log 2 = 1. 4 log T_(2) - 1.4 log 303`
`T_(2) = 369 K`


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