A glass bulb of volume 200cc is sealed at 21^(@)c. If the pressure of the gas inside the bulb is 1.25 xx 10^(-4) cmof Hg, calculate the number of molecules inside the bulb. (Avagadro's number = 6.0225 xx 10^(23), R = 8.314 xx 10^(-7) erg/mole - K )

A glass bulb of volume 200cc is sealed at 21^(@)c. If the pressure of

1.	A glass bulb of volume 200cc is sealed at 21^(@)c. If the pressure of the gas inside the bulb is 1.25 xx 10^(-4) cmof Hg, calculate the number of molecules inside the bulb. (Avagadro's number = 6.0225 xx 10^(23), R = 8.314 xx 10^(-7) erg/mole - K )
Answer» SOLUTION :VOLUME V =200 `cm^(3)`, pressure P = `1.25 xx 10^(-4)` cm of Hg ` 1.25 xx 10^(-4) xx 13.6 xx 980 ("dyne")/(cm^(2))` T= 273 + 27 = 300 K , Avogadro.s number , N = 6.0225`xx 10^(23)`, R = `8.314 xx 10^(7)` erg/mole - K By ideal gas equation , PV = nRT n `= (PV)/(RT) = (1.25 xx 10^(-4) xx 13.6 xx 980 xx 200)/(8.314 xx 10^(7) xx 300)` moles Number of molecules inside the BULB = number of moles X Avogadro.s number `(1.25 xx 10^(-4) xx 13.6 xx 980 xx 200)/(8.314 xx 10^(7) xx 300) xx 6.0225 xx 10^(23) = 8.018 xx 10^(15)`