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A glass flask with volume 200 `cm^(3)` is filled to the brim with mercury at `20^(@)C`. How much mercury overflows when the temperature of the system is raised to `100^(@)C`? The coefficient of linear expansion of the glass is `0.40xx10^(-5)K^(-1)`. Cubical expansion of mercury `=18xx10^(-5)K^(-1)`. |
Answer» The coefficienct of volume expansion for the glass is `gamma_("glass")=3alpha_("glass")=1.2xx10^(-5)K^(-1)` The increase in volume of the glass flask is `DeltaV_("glass")=gamma_("glass")V_(0)DeltaT` `=(1.2xx10^(-5)K^(-1))(200cm^(3))(100^(@)C-20^(@)C)` `=0.19cm^(3)` The increase in volume of the mercury is `DeltaV_("mercury")=gamma_("mercury")V_(0)DeltaT` `=DeltaV_("mercury")=gamma_("mercury")V_(0)DeltaT` `=(18xx10^(-5)K^(-1))(200cm^(3))(100^(@)C-20^(@)C)=2.9cm^(3)` The volume of mercury that overflow is `DeltaV_("mercury")-DeltaV_("glass")=2.7cm^(3)` |
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