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A body of length `1 m` having cross sectional area `0.75 m^(2)` has heat flow through it at the rate of `6000 "Joule"//sec`. Then find the temperature difference if `K = 200 Jm^(-1) K^(-1)`.A. `20^(@)C`B. `40^(@)C`C. `80^(@)C`D. `100^(@)C` |
Answer» Correct Answer - B `Q/t = (KADelta theta)/(l)` `rArr 6000=(200xx0.75xxDelta theta)/(1)` `:. Delta theta = (6000xx1)/(200xx0.75) = 40^(@)C`. |
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