A golfer standing on the ground hits a ball with a velocity of 52m/s at an angle thetaabove the horizontal if tantheta=(5)/(12) find the time for which the ball is at least 15m above the ground? (g=10m//s^(2))

A golfer standing on the ground hits a ball with a velocity of 52m/s a

1.	A golfer standing on the ground hits a ball with a velocity of 52m/s at an angle thetaabove the horizontal if tantheta=(5)/(12) find the time for which the ball is at least 15m above the ground? (g=10m//s^(2))
Answer» Solution :`v_(x) = SQRT(u_(y)^(2)-2gy)` `= sqrt(52xx52xx(5xx5)/(13xx13) - 2xx10xx15) = sqrt(16xx25-300) = 10` `DELTAT = (2u_(y))/(10)= (2XX10)/(10) =` 2s