A golfer standing on the ground hits a ball with a velocity of 52 m/s at an angle theta above the horizontal if tan theta = (5)/(12) find the time for which the ball is at least 15m above the ground ? (g = m//s^(2))

A golfer standing on the ground hits a ball with a velocity of 52 m/s

1.	A golfer standing on the ground hits a ball with a velocity of 52 m/s at an angle theta above the horizontal if tan theta = (5)/(12) find the time for which the ball is at least 15m above the ground ? (g = m//s^(2))
Answer» SOLUTION :`v_(y) = SQRT(u_(y)^(2) - 2gy)` `= sqrt(52 XX 52 xx (5 xx 5)/(13 xx 13) - 2 xx 10 xx 15)` `= sqrt(16 xx 25 - 300) = 10` `Delta t = (2u_(y))/(10) = (2 xx 10)/(10) = 2s`