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A golfgallhasa massof 40 gand a speedof45 m//sif thespeedcan bemeasuredwithinaccuracyof 2%calculatethe uncertainty inthe position |
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Answer» Solution :Uncertainlty invelocity= VELOCITY`xx %100` Accordingof Heisenberguncertaintyprincipleuncertaintyin position`Delta x` `Delta x = (h)/(4pi m Delta V)`wherem= 40 gm =`40 xx 10^(3) KG` `=(6.626 xx 10^(34) j s)/(4(3.14) (40xx 10^(3)kg) (0.90 MS^(1)))` `=0.01465 xx 10^(31) j s^(2) m^(-1)kg^(-1)` `=1.465 xx 10^(33) m:., 1 J = 1 kgm^(2) s^(2)` thisisnearly`10^(18) ` timessmallerthan thediameterof a typicalatomicnucleus . Asmenthonedearlierfor largeparticle.theuncertaintyprinciplesets so meaningfulimitto theprecisionof measurements . |
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