A graph of potential energy V(x) verses x is shown in figure .A particle of energy E_(0) is executing motion in it . Draw graph of velocity and kinetic energy verses x for one complete cycleAFA.

A graph of potential energy V(x) verses x is shown in figure .A partic

1.	A graph of potential energy V(x) verses x is shown in figure .A particle of energy E_(0) is executing motion in it . Draw graph of velocity and kinetic energy verses x for one complete cycleAFA.
Answer» Solution :We KNOW that Total `E = K +U ` `E = K+V(x) "" ( :. U = V(x))` `K = E_(0)-V(x) "" ( :. E =E_(0))` at A , x = 0 ,V(x) = `E_(0)` ` :.K =E_(0)-E_(0)=0` at B , `V(x) lt E_(0)` ` :. K =E_(0)` (Maximum) K=0 At F, the variation is as below , VELOCITY versus x graph : As `KE =1/2 mv^(2)` ` :. ` At A and F , where KE = 0 , v = 0 At C and d , KE is maximum .Therefore , v is `PM` MAX . At B . KE is positive but not maximum . Therefore , v is `pm ` some value ( `lt` max) The variation is shown in the DIAGRAM .