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A graph paper is fitted on a board as shown in figure. Near to the graph paper a spring is placed. A pencil is attached to the end of the spring as shown in figure. The pencil is free to move on the graph paper. A stone of mass 50 gm is placed 1m above the spring. [Spring constant k = 98N/m]1. The energy possessed by the stone due to its height is called_______2. If this stone falls on the spring, find the length of mark that produced on the graph paper due to pencil [The change in P E of stone due to compression may be negleted]3. What will happen to the length of mark, if spring having smaller spring constant is used? Justify. |
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Answer» 1. Potential energy. 2. \(\frac{1}{2}\)kx2 = mg \(\frac{1}{2}\) × 98 × x2 = 50 × 10-3 × 9.8 × 1 x2 = 100 × 104 x = 10cm. 3. The length of mark will be decreased. Compression of spring depends on spring constant. |
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