1.

A graph paper is fitted on a board as shown in figure. Near to the graph paper a spring is placed. A pencil is attached to the end of the spring as shown in figure. The pencil is free to move on the graph paper. A stone of mass 50 gm is placed 1m above the spring. [Spring constant k = 98N/m]1. The energy possessed by the stone due to its height is called_______2. If this stone falls on the spring, find the length of mark that produced on the graph paper due to pencil [The change in P E of stone due to compression may be negleted]3. What will happen to the length of mark, if spring having smaller spring constant is used? Justify.

Answer»

1. Potential energy.

2. \(\frac{1}{2}\)kx2 = mg

\(\frac{1}{2}\) × 98 × x2 = 50 × 10-3 × 9.8 × 1

x2 = 100 × 104

x = 10cm.

3. The length of mark will be decreased. Compression of spring depends on spring constant.



Discussion

No Comment Found

Related InterviewSolutions