1.

A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has (1) no girl (ii) at least one boy and one girl.

Answer»

Given 4 girls and 7 boy's 

(i) no girls:

Total number of selection = 4C7C5 = 1 x (7!/(5! x 2!) = [(7 x 6)/2] = 21 ways

(ii) atleast 1 boy and 1 girls 

Girls × boys 

(a) 4C1 × 7C4 = 7 

(b) 4C2 × 7C3 = 84. 

(c) 4C3 × 7C2 = 210 

(d) 4C4 × 7C1 = 140 

Total number of selection 441 ways .



Discussion

No Comment Found

Related InterviewSolutions