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A group consists of 7 boys and 5 girls. Find the number of ways in which a team of 5 members can be selected so as to have at least one boy and one girl. |
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Answer» Number of ways of selecting 1B and 4G = 7C1 × 5C4 = 35 2 B and 3G = 7C2 × 5C3 = 210 3 B and 2 G = 7C3 × 5C2 = 350 4. B and 1G = 7C4 × 5C1 = 175 Total number of selections = 770. |
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