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A gun is firing bullets with velocity `v_0` by rotating it through `360^@` in the horizontal plane. The maximum area covered by the bullets isA. `pi((u^2)/(g))^2`B. `pi((u^2)/(2 g))^2`C. `pi((u)/(g))^2`D. `pi((u)/(2 g))^2` |
Answer» Correct Answer - A (a) A bullet fired at angle `45^@` will fall maximum away, and all other bullets will fall with this bullet fired at `45^@`. `R_(max) = (u^2)/(g)` Maximum area covered `= pi R_(max)^2 = pi ((u^2)/(g))^2`. |
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