A gun weighing 25 kg fires a bullet weighing 30 g with the speed of 200 ms^(-1). What is the speed of recoil of the gun?

A gun weighing 25 kg fires a bullet weighing 30 g with the speed of 20

1.	A gun weighing 25 kg fires a bullet weighing 30 g with the speed of 200 ms^(-1). What is the speed of recoil of the gun?
Answer» Solution :Mass of the GUN M = 25 kg Mass of the bullet `m = 30g = 30 xx10^(-3) kg` Speed of bullet `v = 200 ms^(-1)` Speed of gun V = ? The motion is in one dimension. As per law of conservation of momentum, `MV = mv = 0` `V=(-mv)/(M)` ` V = (-30 xx 10^(-3) xx 200)/(25)= - 240 xx 10^(-3) ms^(-1)` The negative sign SHOWS that the gun moves in the OPPOSITE direction of the bullet. Further the magnitude of the recoil speed is very small compared to the bullet.s speed.