1.

A gun weighing 25 kg fires a bullet weighing 30 g with the speed of 200 ms^(-1). What is the speed of recoil of the gun?

Answer» <html><body><p></p>Solution :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/gun-1014044" style="font-weight:bold;" target="_blank" title="Click to know more about GUN">GUN</a> M = 25 kg <br/>Mass of the bullet `m = 30g = 30 xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) kg` <br/>Speed of bullet `v = 200 ms^(-1)` <br/>Speed of gun V = ? <br/> The motion is in one dimension. As per law of conservation of momentum, <br/> `<a href="https://interviewquestions.tuteehub.com/tag/mv-1082193" style="font-weight:bold;" target="_blank" title="Click to know more about MV">MV</a> = mv = 0` <br/> `V=(-mv)/(M)` <br/> ` V = (-30 xx 10^(-3) xx 200)/(25)= - 240 xx 10^(-3) ms^(-1)` <br/>The negative sign <a href="https://interviewquestions.tuteehub.com/tag/shows-1206590" style="font-weight:bold;" target="_blank" title="Click to know more about SHOWS">SHOWS</a> that the gun moves in the <a href="https://interviewquestions.tuteehub.com/tag/opposite-1137237" style="font-weight:bold;" target="_blank" title="Click to know more about OPPOSITE">OPPOSITE</a> direction of the bullet. Further the magnitude of the recoil speed is very small compared to the bullet.s speed.</body></html>


Discussion

No Comment Found