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A H–atom in ground state has time period T = 1.6 × 10–16 sec. find the frequency of electron in first excited state(1) 7.8 × 1014 (2) 7.8 × 1016 (3) 3.7 × 1014 (4) 3.7 × 1016 |
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Answer» Answer is (1) T ∝ r/v ∝ n2/z ∝ n/z ∝ n3/z2 T1/T2 = n31/n32 = 1/8 T2 = 8T1 = 8 × 1.6 × 10–16 = 12.8 × 10–16 f2 = {1}/{12.8 x 10-16} ≈ 7.8 x 1014 |
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