A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iv) period

A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where '

1.	A harmonic osillator is represented by y=0.5cos (1500pi t+0.8) where 'y' and 't' are in 'm' and 's' respectively. Calculate (iv) period
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Given, `y=0.5cos(1500pit+0.8)=0.5sin((<a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a>)/(2)-1500pit-0.8)=0.5sin[-1500pit-(0.8-(pi)/(2))]` <br/> `y=-0.5sin[1500pit+(0.8-(pi)/(2))]` <br/> Now (iv) `"period "=(1)/("<a href="https://interviewquestions.tuteehub.com/tag/frequency-465761" style="font-weight:bold;" target="_blank" title="Click to know more about FREQUENCY">FREQUENCY</a>")=(1)/(750)=0.00133=1.33xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)s.`</body></html>