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| 1. |
A heat engine works between a source and a sink maintaned at constant temperatures `T_(1)` and `T_(2)`. For the efficiency to be greatestA. `T_(1)`m and `T_(2)`. Should be highB. `T_(1)` and `T_(2)` should be lowC. `T_(1)` should be low and `T_(2)` should be highD. `T_(1)` should be high and `T_(2)` should be low |
| Answer» `eta=1-(T_(2))/(T_(1))` | |