A heat source at T=103 K is connected to another heat reservoir at T=102 K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 WK−1m−1, the energy flux through it in the steady state is:

A heat source at T=103 K is connected to another heat reservoir at T=1

1.	A heat source at T=103 K is connected to another heat reservoir at T=102 K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 WK−1m−1, the energy flux through it in the steady state is:
Answer» A heat source at $T = 10^{3} K$ is connected to another heat reservoir at $T = 10^{2} K$ by a copper slab which is $1 m$ thick. Given that the thermal conductivity of copper is $0.1 {WK}^{- 1} m^{- 1}$ , the energy flux through it in the steady state is:

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A heat source at T=103 K is connected to another heat reservoir at T=102 K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 WK−1m−1, the energy flux through it in the steady state is:

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