A heavenly body is observed from two diametrically opposite points A and B on the earth. The angle substended at the heavenly body is 2.9 xx 10^(-4) rad. Given the diameter of Earth to be about 1.28 xx 10^(7) Compute the distance of the heavenly body from the earth.

A heavenly body is observed from two diametrically opposite points A a

1.	A heavenly body is observed from two diametrically opposite points A and B on the earth. The angle substended at the heavenly body is 2.9 xx 10^(-4) rad. Given the diameter of Earth to be about 1.28 xx 10^(7) Compute the distance of the heavenly body from the earth.
Answer» `2.267xx10^(-11) m` `4.413xx10^(7)m` `4.413xx10^(10)` `4.413xx10^(10)m` Solution :`D=(b)/(theta)=(1.28xx10^(7)m)/(2.9xx10^(-4)rad)=4.413xx10^(10)m`