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A heavy nucleus at rest breaks into two fragments which fly off with velocities in the ratio `8 : 1`. The ratio of radii of the fragments is.A. `1 : 2`B. `1:4`C. `4:1`D. `2:1` |
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Answer» Correct Answer - A By conservation of momentum, `m_(1)v_(1)=m_(2)v_(2)` `implies " "(v_(1))/(v_(2))=8/1=(m_(2))/(m_(1))" "...(i)` Also, from `r propA^(1//3),` `therefore" "(r_(1))/(r_(2))=((A_(1))/(A_(2)))^(1//3)=((1)/(8))^(1//3)=1/2` |
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