1.

A heavy particle is tied to the end A of a string of length 1.6 m. Its other end O is fixed. It revolves as a conical pendulum with the string making 60^(@) with the vertical. Then (take g = 9.8 m//s)

Answer»

Its period revolution is `(4PI)/(7) ` sec
The tension in the string is DOUBLED the weight of the particle
The SPEED of the particle = `2.8 sqrt(3) m//s`
The centripetal ACCELERATION of the particle is `9.8 m//s^(2)`

Answer :A::B::C::D


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