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A heavy small sized sphere is suspended by a string of length 2. The sphere is rotated uniformly in a horizontal circle with the string making an angle theta with the vertical. The time period of this conical pendulum is |
Answer» <html><body><p>`2 pisqrt((<a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> tantheta)/( g))`<br/>`2 <a href="https://interviewquestions.tuteehub.com/tag/pi-600185" style="font-weight:bold;" target="_blank" title="Click to know more about PI">PI</a> sqrt((l <a href="https://interviewquestions.tuteehub.com/tag/costheta-2550146" style="font-weight:bold;" target="_blank" title="Click to know more about COSTHETA">COSTHETA</a>)/(g))`<br/>`2 pisqrt((1)/(g))`<br/>`2 pi sqrt((l costheta)/(g))`</p>Solution :`2 pi sqrt((l costheta)/(g))`</body></html> | |