1.

A helicopter of mass 2000 kg rises with a vertical acceleration of 15 ms^(-2) The total mass of the crew and passengers is 500kg Give the magnitude and direction of the (a) force on the floor of the helicopter by the crew and passengers (b) action of the rotor of the helicopter on the surrounding air (c) force on the helicopter due to the surrounding air (g = 10ms^(-2)) .

Answer»

Solution :Here, ` m_(1) = 2000 kg , a = 15 ms^(-2) , m_(2) = 500 kg, g = 10 ms^(-2)`
(a) Force on the floor of the HELICOPTER by the crew and passenger ` m_(2) (g + a) = 500 (10+5) = 12500 N = 12.5 xx 10^(3)N`
(B) Action of rotor of helicopter on the surrounding air
` (m_(1) + m_(2)) (g+a) = (2000 + 5000) (10+ 5) = 2500 xx 25 = 6.25 xx 10^(4) N ` This force is downwards
(C) Force on the helicopter due to surrounding air = reaction of force in (b) ` = 6.25 xx 10^(4) N ` upwards .


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