Saved Bookmarks
| 1. |
A hemisphere of radius R and of mass 4m is free to Slide with its base on a smooth horizontal table. A particle mass m is placed on the top of the hemisphere. Find the angular velocity of the particle relative to hemisphere at an angular displacement theta when velocity of hemisphere has become v. |
|
Answer» Solution :Actual velocilty of ball is `v_(1)` is horizontal direction. ` :. v_(1)-(-v)=v_(rel)costheta` `:. v_(1)+v=v_(rel) costheta`……….i Applying conservation PRINCIPLE of momentum in horizotal direction. `P_(ix)=P_(fx)` `0=mv_(1)-4mv` `:. v_(1)=4V`.......ii Applying mechanic energy conservation principle. Loss in `PE=` gain in `KE` `mg(r-rcostheta)=1/2m[sqrt(v_(1)^(2)+(v_(rel)sitheta)^(2))]^(2)+1/24mv^(2)`.........IIII after solving eqn i , ii , iii `v_(rel)=(5v)/(costheta)` `:. omega_(rel)=v_(rel)/R=(5v)/(Rcostheta)` |
|