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A hemispherical bowl is made of iron. It is 1 cm thick and the out diameter is 12 cm. Find how much of iron is required to cast the iron bowl in cm3(round off to nearest whole number)?1. 191 cm32. 157 cm33. 127 cm34. 210 cm3 |
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Answer» Correct Answer - Option 1 : 191 cm3 Given: Outer diameter = 12 cm Outer radius(R) = 12/2 = 6 cm Thickness = 1 cm ∴ Inner radius(r) = Outer radius – thickness = (6 – 1) cm = 5 cm Formula used: Volume of a Hemispherical bowl = (2/3)π(R3 – r3) Calculation: ∵ Volume of a Hemispherical bowl = (2/3)π(R3 – r3) = (2/3) × π × [(6)3 – (5)3] = (2/3) × (22/7) × (216 – 125) = (2/3) × (22/7) × 91 = (182/3) × (22/7) = 190.6 cm3 ≈ 191 cm3 |
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