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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of the plating it on the inside at the rate of Rs. 4 per 100 cm2. |
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Answer» Surface area of a hemisphere = 2πr2 Given, diameter of the hemisphere bowl is 10.5 cm Surface area of the bowl = 2 × (22/7) × (10.5/2)2 = 173.25 cm2 Given, cost of the plating it on the inside at the rate of Rs. 4 per 100 cm2 Cost of plating the hemisphere bowl = \(\frac{4}{100}\times\) 173.25 = Rs. 6.93 |
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