

InterviewSolution
Saved Bookmarks
1. |
A hemispherical bowl of radius R carries a uniform surface charge density of `sigma`. Find potential at a point P located just outside the rim of the bowl (see figure). Also calculate the potential at a point A located at a distance R/2 from the centre on the equatorial plane. |
Answer» Correct Answer - At both P and A the potential is `(sigmaR)/(2epsilon_(0))` |
|