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A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with an initial speed of 15ms^(-1) Neglecting air resistance, find the time taken by the stone to reach the ground and the speed with which it hits the ground? (g=9.8ms^(-2)) |
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Answer» Solution :TIME =10 SECONDS `V=sqrt(V_(s)^(2)+V_(y)^(2))=sqrt(15^(2)+98^(2))=99.1ms^(-1)` |
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