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A hollow prism of base a square of side 16 centimetres contains water 10 centimetres high. If a solid cube of side 8 centimetres is immersed in it, by how much would the water level rise? |
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Answer» When a solid cube is immersed into water, the volume of water is raised. Sum of the volume of the water at first time and volume of the solid cube immersed equally to the product of base area and height of water level now. Volume of the water at first = Base area × height = 16 × 16 × 10 = 2560 cm3 Volume of the solid cube when edges are 8 cm = 8 × 8 × 8 = 512 cm3 Height at first = 10 cm Water level raised = 12 -10 = 2 cm |
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