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A hollow sphere rolls on a horozontal surface without slipping. Then percentages of rotational kinetic energy in total energy isA. `60%`B. `40%`C. `72%`D. `28%` |
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Answer» Correct Answer - B `(KE_("rot"))/(KE_("roll"))=(K^(2)//R^(2))/(1+K^(2)//R^(2))` `=((2)/(3))/(1+(2)/(3))=((2)/(3))/((7)/(3))=(2)/(7)=0.28=28%`. |
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