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A homogeneous magnetic field B is perpendicular to a sufficiently long trach of width l which is horizontal A frictionless conducting resistanceless rod of mass m stradless the two rails of the track as shown in the figure. Entire arrangement lies in horizontal plane. For the situation suggested in column-II match the appropriate entries in column-I the rails are also resistancesless. |
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Answer» Correct Answer - [(A)PQ;(B)PQ;(C)R;(D)PST] (A) `(V-Blv)/R=i` `F=(V-Blv)/R xx Bl` (B) `ilB =ma Rightarrow (lBdQ)/dt=(mdv)/(dt) Rightarrow (BlQ)/m` `U_(i) gt U_(f)` because energy is dissipated in em radiator (C) No energy dissipated as no resistance R rightarrow Red executes SHM `F=ilB to left Rightarrow f_(ext) to right` `F=ilB (Ldi)/(dt)=Blv Rightarrow` not possible to move with constant v |
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