Saved Bookmarks
| 1. |
A horizontal platform with an object placed on it is executing SHM in the vertical direction. The amplitude of oscillation is 3.92xx 10^(-3)m. What must be the least period of these oscillations, so that the object is not detached from the platform? |
|
Answer» `0.1256 s` For `R= 0, mg= ma implies mg= m A omega^(2)` `implies omega = sqrt(g"/"A) = sqrt((9.8)/(3.92xx 10^(-3)))= 50` `implies T= (2pi)/(omega)= (2pi)/(50)= 0.1256s`.
|
|