1.

A horizontal platform with an object placed on it is executing SHM in the vertical direction. The amplitude of oscillation is 3.92xx 10^(-3)m. What must be the least period of these oscillations, so that the object is not detached from the platform?

Answer»

`0.1256 s`
`0.1356 s`
`0.1456 s`
`0.1556 s`

SOLUTION :According to FIGURE `MG-R = ma` (a= acceleration)
For `R= 0, mg= ma implies mg= m A omega^(2)`
`implies omega = sqrt(g"/"A) = sqrt((9.8)/(3.92xx 10^(-3)))= 50`
`implies T= (2pi)/(omega)= (2pi)/(50)= 0.1256s`.


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