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A horizontal platform with an object placed on it is executing SHM in the vertical direction. The amplitude of oscillation is 3.92xx 10^(-3)m. What must be the least period of these oscillations, so that the object is not detached from the platform? |
Answer» <html><body><p>`0.1256 s`<br/>`0.1356 s`<br/>`0.1456 s`<br/>`0.1556 s`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :According to <a href="https://interviewquestions.tuteehub.com/tag/figure-987693" style="font-weight:bold;" target="_blank" title="Click to know more about FIGURE">FIGURE</a> `<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>-R = ma` (a= acceleration) <br/> For `R= 0, mg= ma implies mg= m A omega^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` <br/> `implies omega = sqrt(g"/"A) = sqrt((9.8)/(3.92xx 10^(-3)))= 50` <br/> `implies T= (2pi)/(omega)= (2pi)/(50)= 0.1256s`. <br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/KPK_AIO_PHY_XI_P2_C14_E06_005_S01.png" width="80%"/></body></html> | |