A horizontal wire `0*1m` long carries a current of `5A`. Find the magnitude and direction of the magnetic field, which can support the weight of the wire. Given the mass of the wire is `3xx10^-3 kg//m` and `g=10ms^-2`.A. `6xx10^-3T`, acting vertically upwardsB. `6xx10^-3T`, acting horizontally perpendicular to wireC. `6xx10^-2T`, acting vertically downwardsD. `6xx10^-2T`, acting horizontally perpendicular to wire

A horizontal wire `0*1m` long carries a current of `5A`. Find the magn

1.	A horizontal wire `0*1m` long carries a current of `5A`. Find the magnitude and direction of the magnetic field, which can support the weight of the wire. Given the mass of the wire is `3xx10^-3 kg//m` and `g=10ms^-2`.A. `6xx10^-3T`, acting vertically upwardsB. `6xx10^-3T`, acting horizontally perpendicular to wireC. `6xx10^-2T`, acting vertically downwardsD. `6xx10^-2T`, acting horizontally perpendicular to wire
Answer» Correct Answer - B Here, mass of wire `m=01xx(3xx10^-3)kg`, `I=5A`, `B=?`, `l=01m` In equilibrium position, `F=IlB=mg` or `B=(mg)/(Il)=((01xx3xx10^-3)xx10)/(5xx01)=6xx10^-3T` The weight of wire can be supported by force F if it is acting vertically upwards (i.e. opposite to the weight of wire). It will be so if the direction of `vecB` is horizontal and perpendicular to wire carrying current.

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