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A horizontally oriented copper rod of length / is rotating about a vertical axis passing through its middle. Calculate the rotation frequency at which the rod ruptures. Breaking or rupture strength of copper is sigma and density of copper is rho.

Answer» <html><body><p><br/></p>Answer :`omega=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>((<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> sigma)/(rho l^(2)))(or)n=(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>) sqrt((8 sigma)/(rho l^(2)))`</body></html>


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