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InterviewSolution
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A hot solid of mass 60g at 100°C is placed in 150 g of water at 20°C. The final steady temperature recorded is 25°C. Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 J kg-1 °C-1 ] |
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Answer» Heat gained = Heat los 150 x 4.2 x (25 - 20) = 60 x c x (100 - 25) 150 x 4.2 x 5 = 60 x c x 75 c = 0.7 Jg-1 °C-1 |
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