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A hunter aims his gun fires a bullet directly at monkey on a tree. At the instant the bullet leaves the barrel of the gun, the monkey drops. Will the bullet hit the monkey ? |
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Answer» Solution :Horizontal distance travelled `OB = x = u COS theta t` or `t = (x)/(u cos theta)` For motion of bullet from O to B, the vertical height `AB = u sin theta t - (1)/(2)g t^(2)` Also from figure `MB = x tan theta` Now the height through which monkey falls `y = MA = MB - AB` `= x tan theta - (x tan theta - (g t^(2))/(2)) = (1)/(2) g t^(2)` THUS, in TIME t the bullet passes through A a vertical distance `(1)/(2) g t^(2)` below M. The vertical distance through which the monkey fall in time t. `s = (1)/(2)g t^(2)` Thus, the bullet and the monkey will always reach at point A at the same time. |
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