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A hunterhas a machine gunthat can fire 50 g bullets with a velocityof150ms^(-1). A 60 kg tiger springs at him with a velocity 10ms^(-1) how many bullets must the hunter fire in tothe tiger in order to stop him in his track |
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Answer» Solution :Given: mass of bullet `m=50g = 0.5 kg` Velocityof bullet M= 60 kg VELOCITYV= 10`MS^(-1)` Let nbe thenumber of bulletrequiredto bepumped intotigerto stophim in histrack Accordingto the law of conservation ofmomentum MAGNITUDEOF themomentumof nbullets= magnitudeof tehmomentumof tiger of`nxxmv = Mv` or `n = (MV)/(mv) = (60 xx 10)/( 0.05 xx 150) = 80` `tan theta= (5)/(6)` `theta= tan ^(-1) ((5)/(6))= tan ^(-1)(0.8333)` `=39 .8^(@)` |
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