A hunter’s chance of shooting an animal at a distance r is (a^(2))/(r^(2)) (r gt a) . He fires when r =2aif he misses, he reloads and fires again where r = 3a. Further if he misses at r = 3a thenhe tries again at r = 4a. This process continuous till r= na. If he misses at a distance na,the animal escape. Find odd against the event that animal is shot.

A hunter’s chance of shooting an animal at a distance r is (a^(2))/(

1.	A hunter’s chance of shooting an animal at a distance r is (a^(2))/(r^(2)) (r gt a) . He fires when r =2aif he misses, he reloads and fires again where r = 3a. Further if he misses at r = 3a thenhe tries again at r = 4a. This process continuous till r= na. If he misses at a distance na,the animal escape. Find odd against the event that animal is shot.
Answer» `N + 1 : 2N ` `n + 1 : n -1 ` `n - 1 : 2n ` `n - 1 : n + 1` ANSWER :B

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