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A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000kg . The area of cross - section of the piston carrying the load is 425cm^(2) . What maximum pressure would the smaller piston have to bear ? |
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Answer» SOLUTION :Pressure on thepistondue to car , `thereforeP=(3000xx9.8)/(4.25xx10^(-2))` `=6917xx10^(2)` `=6.92xx10^(5)NM^(-2)` This is the maximum pressure that the SMALLER PISTON would have to bear. |
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