1.

A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000kg . The area of cross - section of the piston carrying the load is 425cm^(2) . What maximum pressure would the smaller piston have to bear ?

Answer»

SOLUTION :Pressure on thepistondue to car ,
`thereforeP=(3000xx9.8)/(4.25xx10^(-2))`
`=6917xx10^(2)`
`=6.92xx10^(5)NM^(-2)`
This is the maximum pressure that the SMALLER PISTON would have to bear.


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