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A hydraulic lift has been constructed to lift vehicles of maximum 3000 Kg. weight. The area of cross-section of the piston’s platform on which the vehicles are lifted is 580 Sq.cm. Calculate the maximum pressure experienced on the small piston. |
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Answer» Area = 580cm2 = 0.058m2 Force = 3000 × 10 = 30000N Pressure = \(\frac{3000}{0.058}\) = 517241.36Pa |
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